Question

A steel cylinder for scuba diving contains 11.1 L of compressed air. The pressure inside the cylinder is
204 atm at a temperature of 24°C.
Calculate the number of moles of air in the cylinder.
Write your answer using three significant figures.
mol air

Answer 1

Answer:

9.28moles

Explanation:

Given parameters:

volume  = 11.1L

pressure  = 204atm

temperature  = 24°C = 24 + 273  = 297K

Unknown:

Number of moles of air in the cylinder  = ?

Solution:

To solve this problem, we apply the ideal gas equation;

         PV = nRT

P is the pressure

V is the volume

n is the number of moles

R is the gas constant  = 0.082atmdm³mol⁻¹K⁻¹

T is the temperature

Now insert the parameters and find n;

     204 x 11.1  = n x 0.082 x 297

    226.4  = 24.4n

        n  = 9.28moles

Answer 2

The number of moles of air in the cylinder is 92.98 moles

From the following parameters given, we are to determine the number of moles of air in the cylinder.

Given that:

• The volume of the steel cylinder = 11.1 L
• The pressure inside the cylinder = 204 atm
• The temperature inside the cylinder = 24°C

The number of moles of air can be determined by using the relation for the ideal gas equation which can be expressed as:

• PV = nRT

where

• n = number of moles

Making (n) the subject of the formula:

$\mathbf{n = \dfrac{PV}{RT}}$

$\mathbf{n = \dfrac{204 \ atm \times 11.1 L}{0.082 \ L .atm/mol .K \times 297 \ K}}$

n = 92.98 moles

Learn more about the ideal gas equation here:

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