If HF=4x+9, EF = 5x+3 , and EF is perpendicular to HF, solve for x.
![If HF4x9 EF 5x3 and EF is perpendicular to HF solve for x class=](https://us-static.z-dn.net/files/d0d/3d2013ee7aab0d4747b4aac45bdb43f4.png)
Answer:
x = 6
Step-by-step explanation:
HF = 4x + 9
EF = 5x + 3
Since FG is perpendicular to EH, ∆EFG and ∆HFG are congruent to each other.
Thus:
HF = EF
4x + 9 = 5x + 3 (substitution)
Collect like terms
4x - 5x = -9 + 3
-x = -6
Divide both sides by -1
x = 6