Question

What is the rotational inertia in units of kgm2 of a long thin rod of mass 1.0 kg and length 0.6 m if it rotates about one of its ends?

Answer 1

Answer:

$I=0.12\ kg-m^2$

Explanation:

Given that,

Mass of a thin rod, m = 1 kg

Length of the rod, l = 0.6 m

We need to find the rotational inertia of the rod if it rotates about one of its ends. It can be given by the formula as follows :

$I=\dfrac{1}{3}ML^2\\\\I=\dfrac{1}{3}\times 1\times (0.6)^2\\\\=0.12\ kg-m^2$

So, the moment of inertia of the rod about one of its ends is $0.12\ kg-m^2$.