Answer:
1) 0.0806 m/s
2) External forces don't act on the system during the jump
Explanation:
velocity of ball ( Vbf )= 15 m/s
mass of quarter back ( Mq )= 80 kg
mass of football ( Mb ) = 0.43 kg
A) How fast will be be moving backward just after releasing the ball
we can determine this speed with the use of conservation of momentum equation
= Mb ( Vbf - Vbi ) = Mq ( Vq )
where Vq = Mb ( Vbf - Vbi ) / Mq
= 0.43 ( 15 m/s - 0 ) / 80 kg
= 0.0806 m/s
B) External forces don't act on the system during the jump