Answer:
The final speed of the electron is 6,497 km/s
Explanation:
Given;
mass of the electron, m = 9.11 x 10⁻³¹ kg
electron potential, V = -120 V
Apply work energy theorem;
¹/₂mv² = eV
Where;
v is the final speed of the electron
e is the charge of the electron, = 1.602 x 10⁻¹⁹ C
[tex]v = \sqrt{\frac{2eV}{m} }\\\\v = \sqrt{\frac{2(1.602*10^{-19})(120)}{9.11*10^{-31}} }\\\\v = 6496473.75 \ m/s\\\\v = 6,497 \ km/s[/tex]
Therefore, the final speed of the electron is 6,497 km/s