If a 3.0 M solution of glucose (C6H12O6), a 2.0 M solution of Na2SO4 and a 1.0 M solution of (NH4)3PO4, is made, which solution will have the lowest vapor pressure, highest boiling point, and lowest freezing point?

Respuesta :

Answer:

[tex]Na_{2}SO_{4}[/tex]

Explanation:

In the case when there are more ions present in the solution so that solution contains less vapour pressure, high boiling point and less freezing point

Given that

[tex]Na_{2}SO_{4} \rightarrow 2Na+ + SO_{4}^{-2}[/tex]

Now the ions present would be

= 2.0 × 3

= 6 ions

These ions represent the greater among all the solutions available

Therefore the [tex]Na_{2}SO_{4}[/tex] is the right answer

The same is to be considered

Answer: Na2SO4

Explanation:

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