Question

Based on the results from this experiment, predict whether some of the following combinations of compounds would precipitate or stay in solution. Explain how you determined that a certain compound should precipitate or be soluble. a. LiOH NaCl b. BaCl2 Na3PO4 c. MgSO4 KOH

Answer 1

Answer:

* No precipitate: $LiOH(aq)+NaCl(aq)\rightarrow LiCl(aq)+NaOH(aq)$

* Precipitate: $3BaCl_2(aq) +2Na_3PO_4(aq) \rightarrow Ba_3(PO_4)_2(s)+6NaCl(aq)$

* Precipitate: $MgSO_4(aq)+2KOH(aq)\rightarrow Mg(OH)_2(s)+K_2SO_4(aq)$

Explanation:

Hello!

In this case, since these all are double displacement reactions, in which the cations and anions are exchanged, we can write the resulting chemical reactions as follows:

a. LiOH and NaCl: No precipitate is formed since LiOH and NaOH are both largely soluble in water:

$LiOH(aq)+NaCl(aq)\rightarrow LiCl(aq)+NaOH(aq)$

b. BaCl2 and Na3PO4: barium phosphate precipitate is formed because it has a large molar mass which makes it insoluble in water:

$3BaCl_2(aq) +2Na_3PO_4(aq) \rightarrow Ba_3(PO_4)_2(s)+6NaCl(aq)$

c. MgSO4 and KOH: magnesium hydroxide "milky" precipitate is formed because it is not soluble in water:

$MgSO_4(aq)+2KOH(aq)\rightarrow Mg(OH)_2(s)+K_2SO_4(aq)$

Moreover, we can relate the solubility of a substance by considering its polarity, molar mass and nature; usually, heavy substances tend to be insoluble in water as well as nonpolar compounds.

Best regards!

Answer 2

The combinations which will make precipiate after mixing are BaCl₂ & Na₃PO₄ and MgSO₄ & KOH.

What is precipitate?

Precipitate is a solid substance, which is insoluble in water or in any given solutions and settle down at the bottom of the vessel.

Precipitate will form when substance have higher size of ions which are not attracted by the water ions because of smaller size of water ions.

• Reaction between LiOH & NaCl is shown as:
  LiOH(aq) + NaCl(aq) → LiCl(aq) + NaOH(aq)
• Reaction between BaCl₂ & Na₃PO₄ is shown as:

        BaCl₂(aq) + Na₃PO₄(aq) → Ba₃(PO₄)₂(s) + 6NaCl(aq)

• Reaction MgSO₄ & KOH is shown as:

       MgSO₄(aq) + 2KOH(aq) → Mg(OH)₂(s) + K₂SO₄

Because of the higher size of ions of Ba₃(PO₄)₂ & Mg(OH)₂ they are insoluble in water.

Hence combination of BaCl₂ & Na₃PO₄ and MgSO₄ & KOH will make precipitate.

To know more about precipitation, visit the below link:

https://brainly.com/question/1783904