Respuesta :
Answer:
[tex]924.96\ cm^3[/tex]
Step-by-step explanation:
Given that,
The diameter of a hockey puck, d = 7.6 cm
Height, h = 3.4 cm
We need to find the volume of the volume of a cylindrical package containing six pucks.
Volume of 1 puck,
[tex]V=\pi r^2 h\\\\=3.14\times (3.8)^2\times 3.4\\\\=154.16\ cm^3[/tex]
Volume of 6 pucks,
[tex]V=6\times 154.16\ cm^3\\\\=924.96\ cm^3[/tex]
So, the volume of the 6 puck is [tex]924.96\ cm^3[/tex].
Given the dimensions of a single hockey puck, we want to find the volume of a cylindrical package containing six pucks. We will see that the volume must be 925 cm^3
So the volume of a cylinder of diameter D and height H is:
V = 3.14*(D/2)^2*H
Here we have:
- D = 7.6cm
- H = 3.4cm.
Then the volume of each single puck is:
V = 3.14*(7.6cm/2)^2*3.4cm = 154.16cm^3
Then the volume of a package that contains 6 of these must have at least 6 times that volume:
6*V = 6*154.16cm^2 = 924.96 cm^3
Rounding to the next cubic centimeter we get 925 cm^3
So the volume of the package must be 925 cm^3
If you want to learn more about volume, you can read:
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