Question

A 200 W light bulb connected across a 110 V dc power supply. (A) What current will flow through this bulb? (B) What is the resistance of the light bulb?

Answer 1

Answer:

I=1.8amps

R=60.5ohms

Explanation:

Step one:

given data

power = 200W

voltage = 110v

. (A) What current will flow through this bulb

we know that the formula relating power, current and voltage is

P=IV

I=P/V

I=200/110

I=1.8amps

(B) What is the resistance of the light bulb?

we know that the formula relating resistance power and voltage is

$P=\frac{V^2}{R}$

substituting our data we have

$200=\frac{110^2}{R}$

cross multiply we have

$200*R=110^2\\\\200*R=12100$

divide both sides by 200

we have

R=12100/200

R=60.5ohms

Answer 2

(A) The current will flow through this bulb will be 1.8amps

(B) The resistance of the light bulb will be 60.5ohms.

What is resistance?

Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

The given data in the problem is;

P is the power= 200 W

V is the voltage= 110 V

I is the current

R is the resistance

(A)  The current will flow through this bulb will be 1.8amps

The relationship between the power and the voltage is given by;

$\rm P=IV\\\\\ I=\frac{P}{V} \\\\ I=\frac{200}{110} \\\\\ I=1.8amps$

Hence the current will flow through this bulb will be 1.8amps

(B) The resistance of the light bulb will be 60.5ohms.

The relationship between the power and the resistance is given by;

$\rm P= \frac{V^2}{R} \\\\ \rm R= \frac{V^2}{P} \\\\ \rm R= \frac{(110)^2}{200} \\\\ \rm R=60.5 \ ohm$

Hence he resistance of the light bulb will be 60.5ohms.

To learn more about the resistance refer to the link;

https://brainly.com/question/20708652