Question

Calculate the wavelengths of a 1530 kHz AM radio signal, a 105.1 MHz FM radio signal, and a 1.90 GHz cell phone signal.

Answer 1

Answer:

196.07 m, 2.85 m and 0.15 m

Explanation:

Frequency of AM radio signal, f₁ = 1530 kHz

Its wavelength can be given by :

$\lambda_1=\dfrac{c}{f_1}\\\\=\dfrac{3\times 10^8}{1530\times 10^3}\\\\=196.07\ m$

Frequency of FM radio signal, f₂ = 105.1 MHz

Its wavelength can be given by :

$\lambda_2=\dfrac{c}{f_2}\\\\=\dfrac{3\times 10^8}{105.1\times 10^6}\\\\=2.85\ m$

Frequency of cell phone signal, f₃ = 1.9 GHz

Its wavelength can be given by :

$\lambda_2=\dfrac{c}{f_2}\\\\=\dfrac{3\times 10^8}{1.9\times 10^9}\\\\=0.15\ m$

Hence, the required wavelengths are 196.07 m, 2.85 m and 0.15 m respectively.