Answer:
The radius is [tex]r = 9183.7 \ m[/tex]
Explanation:
From the question we are told that
The speed of the jet plane is [tex]v = 600 \ m/s[/tex]
The acceleration is [tex]a = 4g[/tex] here [tex]g = 9.8 \ m/s^2[/tex] so [tex]a = 4* 9.8 = 39.2 \ m/s^2[/tex]
Generally the centripetal acceleration of the jet just before it pulled out of the circular section dive is mathematically represented as
[tex]a = \frac{v^2}{r}[/tex]
=> [tex]r = \frac{v^2}{a}[/tex]
=> [tex]r = \frac{600^2}{39.2}[/tex]
=> [tex]r = 9183.7 \ m[/tex]
