Question

Direction: Complete the table below by checking the description of roots and solve
the value of discriminant b2 - 4ac.
Description of roots
Value of
discriminant
b2 - 4ac
Equation
Equal
Not
Equal
Real
Non Real
1.4x2 + 4x + 1 = 0​



pls,, help me

Answer 1

Answer:

The polynomial $1.4\cdot x^{2}+4\cdot x +1=0$ have real roots.

Step-by-step explanation:

The second-order polynomial required to be analyzed is $1.4\cdot x^{2}+4\cdot x +1=0$. From Algebra we remember that second-order polynomials of the form $a\cdot x^{2}+b\cdot x +c =0$ can be solved by the Quadratic Formula, of which we can determined if their roots are either real or complex by the ressource of the discriminant, defined as:

$D=b^{2}-4\cdot a\cdot c$ (1)

Roots are real if and only if $D \ge 0$, otherwise roots are complex.

If we know that $a = 1.4$, $b = 4$ and $c = 1$, then the value of the discriminant is:

$D = 4^{2}-4\cdot (1.4)\cdot (1)$

$D = 10.4$

The polynomial $1.4\cdot x^{2}+4\cdot x +1=0$ have real roots.