Respuesta :

Answer:

a(2y - 1)(y + 3)

Step-by-step explanation:

Factor the following:

[tex] \longrightarrow [/tex] 2ay² + 5ay - 3a

Factor a out of 2ay² + 5ay - 3a:

[tex] \longrightarrow [/tex] a(2y² + 5y - 3)

The coefficient of y² is 2 and the constant term is -3. The product of 2 and -3 is -6. The factors of -6 which sum to 5 are -1 and 6.

So,

[tex] \longrightarrow [/tex] a(2y² + (6 - 1)y - 3)

[tex] \longrightarrow [/tex] a(2y² + 6y - y - 3)

[tex] \longrightarrow [/tex] a(2y(y + 3) - 1(y + 3))

Factor y + 3 from 2y(y + 3) - 1(y + 3):

[tex] \longrightarrow [/tex] a(2y - 1)(y + 3)

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