Question

Provided that 2a+b=7 and
3a - 2b=3, by how much is 7a
greater than 10?​

Answer 1

Answer:

a=2.42, b=2.16

16.94>10

Step-by-step explanation:

We are given: 2a+b =7 and 3a-2b=3 , We need to find how much is 7a greater than 10.

First we need to solve equations to find value of a

$2a+b =7---eq(1)\\ 3a-2b=3---eq(2)$

Multiply eq(1) by 2 and add both equations

$4a+2b =14\\ 3a-2b=3\\------\\7a=17\\a=\frac{17}{7}\\a=2.42$

Putting value of a in eq(1) to find b

$2a+b=7\\2(2.42)+b=7\\4.84+b=7\\b=7-4.84\\b=2.16$

Now, a = 2.42 and b=2.16

Finding by how much is 7a  greater than 10

$7a>10$

Putting a = 2.42

$7a>10\\7(2.42)>10\\16.94>10$