Respuesta :
Required Answer:
As per the provided question, we have to find the value of x. So, we can easily find the value of x by transposition method.
[tex] \sf \red { 1.5x + 1.3x = -8.4 } [/tex]
[tex] \sf {\implies 2.8x = -8.4 } [/tex]
[tex] \sf {\implies x =\dfrac{ -8.4 }{2.8}} [/tex]
[tex] \sf {\implies x =\dfrac{ -84 \times \cancel{10} }{28 \times \cancel{10}}} [/tex]
[tex] \sf {\implies x =\dfrac{ -84 }{28}} [/tex]
[tex] \sf {\implies x = -3} [/tex] [tex] \purple {\bigstar} [/tex]
Let's check it too by verifying it!
Verification:
Just substitute the value of x in L.H.S .
[tex] \sf \red { 1.5x + 1.3x = -8.4 } [/tex]
Therefore
[tex] \sf {\implies 1.5(-3) + 1.3(-3)= -8.4 } [/tex]
[tex] \sf {\implies -4.5+ (-3.9)= -8.4 } [/tex]
[tex] \sf {\implies -4.5-3.9= -8.4 } [/tex]
[tex] \sf \purple {\implies -8.4= -8.4 } [/tex]
[tex] \sf {\therefore L.H.S= R.H.S } [/tex]