Question

Write an equation for a line that is perpendicular to the line y=-1/3x and passes through the point (0,-10)

Answer 1

Answer:

y = -3x -10

Step-by-step explanation:

The slope will be the reciprocal which is -3x

y=-3x+a

-10=-3(0) +a

-10=0 + a

a=-10

y= -3x -10

Answer 2

The equation for a line that is perpendicular to the line y=-1/3x and passes through the point (0,-10) is y = 3x - 10

A linear equation is of the form:

y = mx + b

where y, x are variables, m is the slope of the line and b is the y intercept

Two lines are perpendicular if the product of their slopes is -1. That is the slope of one line is the negative inverse of the other line.

The slope of the line perpendicular to  y=-1/3x is 3. Since it passes through the point (0,-10), hence:

$y-y_1=m(x-x_1)\\\\y-(-10)=3(x-0)\\\\y+10=3x\\\\y=3x-10$

Hence the equation for a line that is perpendicular to the line y=-1/3x and passes through the point (0,-10) is y = 3x - 10

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