Question

Which function has a domain of {x | x8}?
O f(x) = x-8 + 1
Of(x)= x+8 -1
Of(x) = x-1 + 8
Of(x) = {x+1-8

Answer 1

The function that has a domain of {x | x ≥ 8} is f(x) = $\sqrt{x-8}$ + 1

Complete question

Which function has a domain of {x | x ≥ 8}?

• f(x) = $\sqrt{x-8}$ + 1
• f(x)= $\sqrt{x+8}$ -1
• f(x) = $\sqrt{x-1}$ + 8
• f(x) = $\sqrt{x+1}$ - 8

How to determine the function?

From the list of options, we can see that the four options are transformed square root functions.

So, for a function to have a domain of {x | x ≥ 8}, the radicand must be x ≥ 8.

So, we start by setting the radicands greater than or equal to 0.

For the first option, we have:

f(x) = $\sqrt{x-8}$ + 1

Set the radicand ≥ 0

x - 8 ≥ 0

Add 8 to both sides

x ≥ 8

Hence, the function that has a domain of {x | x ≥ 8} is f(x) = $\sqrt{x-8}$ + 1

Read more about domain at:

https://brainly.com/question/1770447

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