Which geometric series results in a sum of -69,905
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Using geometric sequence concepts, it is found that the one which results in a sum of -69,905 is:
D. [tex]\sum_{k = 0}^{9} -\frac{1}{5}(4)^k[/tex]
As a sum, it can be represented by:
[tex]\sum_{k = 0}^{n - 1} a_1(q)^k[/tex]
The result of the sum is:
[tex]S = \frac{a_1(1 - q^n)}{1 - q}[/tex]
Item A:
For this sequence, we have that:
[tex]a_1 = \frac{1}{4} = 0.25, n = 8, q = -5[/tex]
Hence, the sum is:
[tex]S = \frac{0.25(1 - (-5)^8)}{4} = -24414[/tex]
Item B:
For this sequence, we have that:
[tex]a_1 = -\frac{1}{4} = -0.25, n = 12, q = 5[/tex]
Hence, the sum is:
[tex]S = \frac{-0.25(1 - (5)^12)}{-4} = -15258789[/tex]
Item C:
For this sequence, we have that:
[tex]a_1 = \frac{1}{5} = 0.2, n = 11, q = -4[/tex]
Hence, the sum is:
[tex]S = \frac{0.2(1 - (-4)^11)}{3} = 279620.3[/tex]
Item D:
For this sequence, we have that:
[tex]a_1 = -\frac{1}{5} = -0.2, n = 10, q = 4[/tex]
Hence, the sum is:
[tex]S = \frac{-0.2(1 - (4)^10)}{-3} = -69905[/tex]
Hence option D is correct.
You can learn more about geometric sequence concepts at https://brainly.com/question/11847927