Carbon-14 has a half life of 5730 years. Consider a sample of fossilized wood that when alive would have contained 24g of C-14 it now contains 1.5g. How old is the sample

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Answer:

5732 years

Explanation:

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The sample of fossilized wood is 22920 years old.

The half life is the time required for a substance to decay to half of its initial value. It is given by:

[tex]N=N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} }[/tex]

Where N is the final value of the substance, No is the initial value of the substance, t is the time and [tex]t_\frac{1}{2}[/tex] is the half life.

Given a half live of 5730 years, N = 1.5g, No = 24g. Hence:

[tex]1.5=24(0.5)^\frac{t}{5730} \\\\1/16=(0.5)^\frac{t}{5730} \\\\ln(1/16)=\frac{t}{5730} ln(0.5)\\\\t=22920\ years[/tex]

Therefore the sample is 22920 years old.

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