Peter works as a delivery person for a bike shipping company. The graph shows a linear model for his
delivery times on different days.

(a) what is the equation of the line, first written in point-slope form and then written in slope- intercept form? show how you determined the equation.

(b) based on the linear model, predict how long it initially took peter to deliver his packages (y-intercept) approximately how much did his delivery time decrease per day (slope)? Complete sentences

Peter works as a delivery person for a bike shipping company The graph shows a linear model for his delivery times on different days a what is the equation of t class=

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Answer/Step-by-step explanation:

a. Using a point on the graph, (6, 12), and the slope of the line, we can first generate an equation in the point-slope form, given as [tex] y - b = m(x - a) [/tex], where,

m = slope, and (a, b) is a point on the line.

Using two points, (6, 12) and (3, 21), let's find slope, m.

[tex] slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{21 - 12}{3 - 6} = \frac{9}{-3} = -3 [/tex]

Using a point (6, 12) and slope, m = -3, generate an equation in the point-slope form by substituting a = 6, b = 12, and m = -3 in [tex] y - b = m(x - a) [/tex].

✅Equation in point-slope form would be:

[tex] y - 12 = -3(x - 6) [/tex]

Rewrite this to make it be in the slope-intercept form, [tex] y = mx + b [/tex].

[tex] y - 12 = -3(x - 6) [/tex]

[tex] y - 12 = -3x + 18 [/tex]

Add 12 to both sides

[tex] y = -3x + 18 + 12 [/tex]

[tex] y = -3x + 30 [/tex]

✅The equation in slope-intercept form is [tex] y = -3x + 30 [/tex]

b. ✍️Based on the linear model, [tex] y = -3x + 30 [/tex], the 30 represents b = y-intercept.

✅Therefore, it took Peter 30 mins long initially to deliver his package.

✍️Based on the linear model, [tex] y = -3x + 30 [/tex], "-3" represents the slope.

✅Therefore,  Peter's delivery time decreased 3 mins per day.

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