Question

3.How many grams of lithium nitrate will be needed to
make 250 grams of lithium sulfate? Using the following
equation:
Pb(SO ), + 4 LINO - Pb(NO3), + 2 Li SO
4

Answer 1

Answer:

$m_{LiNO_3}=314gLiNO_3$

Explanation:

Hello!

In this case, for the given chemical reaction:

$Pb(SO_4 )_2, + 4 LiNO_3 \rightarrow Pb(NO_3)_4, + 2 Li_2 SO_4$

We can see a 4:2 mole ratio between lithium nitrate (68.946 g/mol) and lithium sulfate (109.94 g/mol); in such a way, via stoichiometry, the required mass of lithium nitrate to make 250 g of lithium sulfate turns out:

$m_{LiNO_3}=250gLi_2SO_4*\frac{1molLi_2SO_4}{109.94gLi_2SO_4} *\frac{4molLiNO_3}{2molLi_2SO_4} *\frac{68.946gLiNO_3}{1molLiNO_3}\\\\m_{LiNO_3}=314gLiNO_3$

Best regards!