In chickens, feather color is codominant. If a black chicken BB is mated with one that is black and white (BW) what are the chances of having a chicken that is black and white?

Respuesta :

Answer:

1/2

Explanation:

BWxBB= BB BB BW BW      BW is black and white and BB is all black

The chances of having a chicken that is black and white from a mating between a black (BB) chicken with one black and white (BW) chicken will be 50 percent (50%).

In genetics, codominance occurs when two alleles of the same gene are both expressed in heterozygous individuals.

In consequence, in codominance, the phenotype of heterozygous individuals results in a mixture of both codominat alleles.

In this case, the first parent is homo-zygous for the allele 'black' (genotype BB), thereby this individual only can produce gametes with the B allele (100%).

Moreover, the second parent is heterozygous for the alleles 'black' and 'white' (genotype BW), thereby this individual can produce two types of gametes in equal proportion (50%): gametes having 'B' allele and gametes having the 'W' allele.

In consequence, in this case, it is expected to obtain individuals expressing the homo-zygous 'black' phenotype (genotype BB) and individuals expressing the heterozygous 'black and white' phenotype (genotype BW) in equal proportion (i.e., 50% genotype BB, 50% genotype BW) >>

Punnet square (F1):

             W          B

B       1/2 BW    1/2 BB

In conclusion, the chances of having a chicken that is black and white from a mating between a black (BB) chicken with one black and white (BW) chicken will be 50 percent (50%).

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