Question

Find the direction of the sum of
these two vectors:
3.14 m,
30.0°
60.0°
2.71 m

Answer 1

The magnitude of the resultant vector is 4.14m and the direction is 50°.

What is the magnitude of the forces?

The resultant magnitude of the vector is the sum of the algebraic forces acting at the point.

The magnitude of the resultant vector, F is calculated below:

$F = \sqrt{3.14^{2} + 2.71^{2}} = 4.14m$

The direction is given below as follows:

$x = tan^{-1} × \frac{3.14}{2.71} = 50$

Therefore, the magnitude of the resultant vector is 4.14m and the direction is 50°.

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