If RT bisects SU, find each measure ST, RU, SV, SU,
![If RT bisects SU find each measure ST RU SV SU class=](https://us-static.z-dn.net/files/dcc/a4dc5326ff688c34e441090a42c6ad18.jpg)
Answer:
ST = 23
RU = 8
SV = 5
SV = 10
Step-by-step explanation:
Use the knowledge of the properties of a kite to find the measure of ST, RU, SV, and SU as shown below:
✍️Recall: Each pair of adjacent sides of a kite are congruent/equal.
ST and TU are a pair of adjacent sides.
TU = 23
✅Therefore, ST = 23.
RU and RS are a pair of adjacent sides.
RS = 8
✅Therefore, RU = 8.
✍️ Recall: the longer diagonal of a kite bisects the shorter one. This means RT divides SU into two equal parts, namely SV and UV.
Since UV = 5, therefore,
✅SV = 5
SU = UV + SV
✅SV = 5 + 5 = 10
A bisector divides the lines it bisects into equal segments
The measures of ST, RU, SV, SU are 23, 8, 10 and 5 respectively
From the diagram, we have:
[tex]\mathbf{TU = 23}[/tex]
[tex]\mathbf{UV = 5}[/tex]
[tex]\mathbf{RS = 8}[/tex]
Because RT bisects SU, then:
[tex]\mathbf{ST = TU}[/tex]
So, we have:
[tex]\mathbf{ST = 23}[/tex]
Also, we have:
[tex]\mathbf{RU = RS}[/tex]
So, we have:
[tex]\mathbf{RU = 8}[/tex]
Also, we have:
[tex]\mathbf{SV =VU \times 2}[/tex]
[tex]\mathbf{SV =5 \times 2}[/tex]
[tex]\mathbf{SV =10}[/tex]
Lastly, we have:
[tex]\mathbf{SU =VU}[/tex]
[tex]\mathbf{SU =5}[/tex]
Hence, the measures of ST, RU, SV, SU are 23, 8, 10 and 5 respectively
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