Question

A soccer ball is kicked at an angle of 40 degrees with an initial velocity of
14 m/s. What is the horizontal velocity in m/s? (Do not state units, and give
answers to the hundredths place.) *

Answer 1

Answer:

$v_x=10.72\ m/s$

Explanation:

Projectile Motion

It's the type of motion that experiences an object launched near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, and θ the initial launch angle, the two components of the velocity are given by:

$v_x=v_o\cos\theta$

$v_y=v_o\sin\theta-g.t$

The soccer ball is kicked at an angle of 40° with an initial speed of vo=14 m/s.

The horizontal component is:

$v_x=14\cos 40^\circ$

Calculating:

$v_x=14\cdot 0.766$

$\mathbf{v_x=10.72\ m/s}$