Respuesta :
Complete Question
The complete question is shown on the first uploaded image
Answer:
The value is [tex]F_f = 3 * -4[/tex]
Explanation:
From the question we are told that
The mass of the block is [tex]m = 3 \ kg[/tex]
The initial speed of the block before entering the rough section is [tex]u = 5 \ m/s[/tex]
The time taken is t = 0.5 s
The speed with which the block leaves the rough section is [tex]v = 3 \ m/s[/tex]
Generally from kinematic equation
[tex]v = u + at[/tex]
=> [tex]a = \frac{v - u }{t}[/tex]
=> [tex]a = \frac{3 - 5 }{0.5}[/tex]
=> [tex]a = - 4[/tex]
Generally the magnitude of the average frictional force is mathematically represented as
[tex]F_f = m * a[/tex]
=> [tex]F_f = 3 * -4[/tex]
=> [tex]F_f = -12 \ N[/tex]
The negative sign show that the force is acting in the opposite direction to the direction of motion of the block
![Ver imagen okpalawalter8](https://us-static.z-dn.net/files/d97/c799e89b9df437b1ba90e0d9b5b10c84.png)
The frictional force between the block and the horizontal surface is 12.1 N.
The given parameters;
- mass of the block, m = 3 kg
- initial speed of block, u = 5 m/s
- time of motion, t = 0.5 s
- final speed, v = 3 m/s
The acceleration of the block is calculated as follows;
[tex]a = \frac{\Delta v}{t} \\\\a = \frac{5- 3}{0.5} \\\\a = 4 \ m/s^2[/tex]
The coefficient of friction between the block and the horizontal surface is calculated as;
[tex]\mu_k = \frac{a}{g} \\\\\mu_k = \frac{4}{9.8} \\\\\mu_k = 0.41[/tex]
The frictional force between the block and the horizontal surface is calculated as follows;
[tex]F_f = \mu_k F_n\\\\F_f = \mu_k mg\\\\F_f = 0.41 \times 3 \times 9.8\\\\F_f = 12 .1 \ N[/tex]
Thus, the frictional force between the block and the horizontal surface is 12.1 N.
"Your question is not complete, it seems to be missing the following information;"
A block of mass 3 kg slides along a horizontal surface that has negligible friction except for one section, as shown above. The block arrives at the rough section with a speed of 5 m/s and leaves it 0.5 s later with a speed of 3 m/s. What is the magnitude of the average frictional force exerted on the block by the rough section of the surface?
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