The diagram below depicts a game of tug of war between Person A and Person B. Person A pulls the rope with a force of FA while Person B pulls with force FB.

If FB is greater than FA, what describes the movement of the center flag?

It moves in the direction of FB at a changing rate of speed.

It moves in the direction of FA at a constant rate of speed.

It moves in the direction of FB at a constant rate of speed.

It moves in the direction of FA at a changing rate of speed.

In order to answer this question, the Newton's Second Law of motion shall be used. The Newton's Second Law of Motion states that when an unbalanced force is applied to an object, it produces an acceleration in that object. This acceleration is in the direction of the unbalanced force. So, when the person A and person B are applying forces FA and FB, the force FB is greater than FA. Hence, the unbalanced force will be in the direction of FB, the greater force. So, the flag will move in the direction of FB at a acceleration (rate of speed). So, the correct option is:

It moves in the direction of FB at a constant rate of speed.