A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and vertical components of the skier's displacement?
Total displacement along the length of mountain is given as L = 235 m angle of mountain with horizontal = 35 degree now we will have horizontal displacement as x = L cos35 x = 235 cos35 = 192.5 m similarly for vertical displacement we can say y = L sin35 y = 235 sin35 = 134.8 m
