The inverse of a function reverses the operation of a function
The statement that provides the correct analysis of Maggie's claim is the following option;
Maggie's claim is incorrect because when g(x) is substituted into every occurrence of x in f(x), f(g(x)) = x - 8; therefore, g(x) is not the inverse of f(x)
Question: The functions in the question are presented as follows;
[tex]g(x) = \dfrac{x}{3} - 4[/tex]
f(x) = 3·x + 4
Required:
The statement that provides a correct analysis of Maggie's claim
Solution:
The inverse of f(x) is found as follows;
y = 3·x + 4
[tex]x = \dfrac{y - 4}{3}[/tex]
Therefore;
[tex]f^{-1}(x) = \dfrac{x - 4}{3}[/tex]
The inverse of a function above was found by making x the subject of the
function f(x), therefore, when the inverse f⁻¹(x) is substituted into all
occurrence of x in f(x), we get x
However, when g(x) is substituted into every occurrence of x in g(x), we get;
[tex]f \left (g(x) \right) = 3 \times \left (\dfrac{x}{3} - 4 \right)+ 4 = x - 8 \neq x[/tex]
Therefore, the given function g(x) is not the inverse of the function f(x) and the correct option is as follows;
Maggie's claim is incorrect because when g(x) is substituted into every occurrence of x in f(x), f(g(x)) = x - 8; therefore, g(x) is not the inverse of f(x)
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