Question

Consider the function h(x)=1/2x-3 with a restricted domain of {-2,0,2,10}. What is the range of the function?

Answer 1

Answer: {-4,-3,-2,2} or c on the test nav assessment Question 7.

Step-by-step explanation:

It asks for the range. Range is your output. Which is your y. Plug in your domain (which is your x or input).

Your domain is {-2,0,2,10}

h(-2)=1/2(-2)-3=-4

h(0)=1/2(-0)-3=-3

h(2)=1/2(2)-3=-2

h(10)=1/2(10)-3=2

Actually B. If it’s asking for the restricted domain. Because a restricted domain, is a domain with a denominator. And this doesn’t have a denominator. So it would be all real numbers.

Answer 2

The range of function is {-4, -3, -2, 2} if the function h(x)=1/2x-3 with a restricted domain of {-2,0,2,10}.

What is a function?

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We are assuming the function is:

$\rm h(x) =\dfrac{1}{2}x-3$

The domain of the function:  {-2,0,2,10}

Find the value of the function at points -2, 0, 2, and 10:

h(-2) = 1/2(-2)-3 = -4

h(0) = 1/2(-0)-3 = -3

h(2) = 1/2(2)-3 = -2

h(10) = 1/2(10)-3 = 2

So the range of function will be {-4, -3, -2, 2}

Thus, the range of function is {-4, -3, -2, 2} if the function h(x)=1/2x-3 with a restricted domain of {-2,0,2,10}.

Learn more about the function here:

brainly.com/question/5245372

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