Respuesta :

Answer:

(1). [tex]h(t)=-4(t-1)^2+36[/tex]

(2). 1 minute

Step-by-step explanation:

  • They want you to factorize the equation in such a way that the vertex appears as a number in the equation; and you do that by using a method called completing the square
  • Here is our equation: [tex]h(t)=-4t^2+8t+32[/tex]
  • We factor it by completing the square: But first remember this:
  • A quadratic equation has the general form [tex]f(x)=ax^2+bx+c[/tex]
  • Where a and b are the numbers before x squared and x respectively, and c is the number without an x, and f(x) is the value dependent on x
  • In this case x is t
  • So the steps are as follows
  1. Equate the equation to zero: [tex]-4t^2+8t+32=0[/tex]
  2. Divide each term by the (a) of the equation in this case is it -4, and we get: [tex]t^2-2t-8=0[/tex]
  3. Then take the new (c) to the other side of the equation, in the case we add 8 to both sides to get: [tex]t^2-2t=8[/tex]
  4. Now the tricky part, you have to add to both sides of the equation the square of half of the coefficient of t or number before t, not t squared just t and you get: [tex]t^2-2t+(-1)^2=8+(1)^2[/tex]
  5. Now the left side is in the square form, or it just means when you factor the left side, you get it as the square of a certain single term, in this case we get: [tex](t-1)^2=8+1[/tex]
  6. When we simplify we get: [tex](t-1)^2=9[/tex]
  7. Now any equation in this form, will give you the vertex when you equate the term in parenthesis to zero, and simplify: [tex]t-1=0,t=1[/tex]
  8. [tex]t=1[/tex] is the value of the t or time at the vertex
  9. To write the equation again, multiply every term with the (a) you used to get: [tex]h(t)=-4(t-1)^2+36[/tex] , and this is the equation for #(1)
  • Now here is why we needed to get the vertex; the vertex tells us at what point the height either reaches its maximum/highest level, or where it reaches its minimum/lowest level
  • So since the time (t) at the vertex is 1, in order to find the height at this time, just plug it into the equation:
  • [tex]h(1)=-4((1)-1)^2+36\\h(1)=-4(0)+36\\h(1)=36[/tex] So that's the height at the vertex
  • Now it can either be the maximum/highest height or the minimum/lowest height, in order to know this we check as follows
  • Remember the (a) we used to factor the equation? -4, if the (a) value of a quadratic function is less than 0, then it is a maximum equation, mean whatever vertex you get will be the point where the equation reaches its biggest value.
  • So at a height of 36 meters, and a time of 1 minute, the craft reaches its highest point.
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