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Suppose g(x) = f(x) + k. Identify a value of k that transforms f into g.

Suppose gx fx k Identify a value of k that transforms f into g class=

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Answer:

[tex]k = 5[/tex]

Step-by-step explanation:

Given

[tex]g(x) = f(x) + k[/tex]

Required

Determine the value of k

First, we need to determine the equation of g(x)

Start by calculating the slope (m)

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Where x and y are two corresponding values:

[tex](x_1,y_1) = (1,1)[/tex]

[tex](x_2,y_2) = (0,-3)[/tex]

The slope (m) is:

[tex]m = \frac{-3- 1}{0 - 1}[/tex]

[tex]m = \frac{-4}{- 1}[/tex]

[tex]m = 4[/tex]

The equation is calculated using:

[tex]y - y_1 = m(x - x_1)[/tex]

Where

[tex]m = 4[/tex] and [tex](x_1,y_1) = (1,1)[/tex]

[tex]y - 1 = 4(x - 1)[/tex]

[tex]y - 1 = 4x - 4[/tex]

Make y the subject of formula

[tex]y = 4x - 4 + 1[/tex]

[tex]y = 4x - 3[/tex]

So:

[tex]f(x) = 4x - 3[/tex]

Next, we determine the equation of f(x)

Start by calculating the slope (m)

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Where x and y are two corresponding values:

[tex](x_1,y_1) = (-1,-2)[/tex]

[tex](x_2,y_2) = (0,2)[/tex]

The slope (m) is:

[tex]m = \frac{2- (-2)}{0 - (-1)}[/tex]

[tex]m = \frac{2+2}{0+1}[/tex]

[tex]m = \frac{4}{1}[/tex]

[tex]m = 4[/tex]

The equation is calculated using:

[tex]y - y_1 = m(x - x_1)[/tex]

Where

[tex]m = 4[/tex] and [tex](x_1,y_1) = (-1,-2)[/tex]

[tex]y - (-2) = 4(x - (-1))[/tex]

[tex]y + 2 = 4(x +1)[/tex]

[tex]y + 2 = 4x +4[/tex]

Make y the subject of formula

[tex]y = 4x + 4 - 2[/tex]

[tex]y = 4x + 2[/tex]

So:

[tex]g(x) = 4x + 2[/tex]

Recall that

[tex]g(x) = f(x) + k[/tex]

Make k the subject

[tex]k = g(x) - f(x)[/tex]

Substitute values for g(x) and f(x)

[tex]k = 4x + 2 - (4x - 3)[/tex]

[tex]k = 4x + 2 - 4x + 3[/tex]

[tex]k = 4x - 4x+ 2 + 3[/tex]

[tex]k = 5[/tex]

The transformation that maps f into g is a translation transformation,

involving the addition of k to the value of f(x).

  • The value of k that transforms f into g is; k = -5

Reasons:

Points on the graph of g(x) are; (0, -3) and (0, 1)

[tex]\mathrm{The \ slope \ of \ the \ graph \ of \ g(x)} =\dfrac{-3 - 1}{0 - 1} = 4[/tex]

The equation of g(x) is; y - (-3) = 4·x, which gives;

y = 4·x - 3

The y-intercept = -3

Points on the graph of f(x) are; (-1 -2) and (0, 2)

[tex]\mathrm{The \ slope \ of \ the \ graph \ of \ f(x)} =\dfrac{-2 - 2}{-1 - 0} = 4[/tex]

The equation of f(x) is; y - (-2) = 4·(x - (-1)), which gives;

y = 4·x + 4 - 2 = 4·x + 2

The y-intercept = 2

The slopes of the graphs of f(x) and g(x) are equal, therefore, f(x) ║ g(x)

The difference or the transformation that takes the y-intercept of f(x) to the

y-intercept of g(x) is; k = y-intercept(g(x)) - y-intercept(f(x)) = -3 - 2 = -5

Therefore, k = -5

Which gives;

g(x) = f(x) - 5

The value of k that transforms f into g is; k = -5

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