Question

What is the index of refraction of a material for which the wavelength of light is 0.671 times its value in a vacuum

Answer 1

Explanation:

We need to find the index of refraction of a material for which the wavelength of light is 0.671 times its value in a vacuum.

The wavelength in any medium is given by :

$\lambda_m=\dfrac{\lambda}{n}$

Where, $\lambda$ is wavelength in vacuum and n is refractive index of the medium.

$n=\dfrac{\lambda}{\lambda_m}\\\\n=\dfrac{\lambda}{0.671\lambda}\\\\=\dfrac{1}{0.671}\\\\=1.49$

So, the medium can be PMMA (acrylic, plexiglas, lucite, perspex) which have a refractive index of 1.49.

Answer 2

The index of refraction of the material for which the wavelength of light is 0.671 times, the value of it in a vacuum is 1.49.

What is the index of refraction of a material?

The index of refraction of a material is the ratio of wavelength of the wave in vacuum to the wavelength of the wave in the given medium.

The index of refraction is inversely proportional to the wavelength. It can be find out using the following formula.

$n=\dfrac{\lambda}{\lambda_m}$

Here, (λ) is the wavelength in vacuum and (λm) is the wavelength in a medium.

The index of refraction of a material for which the wavelength of light is 0.671 times its value in a vacuum (0.671×λ).

Plug in the values in the above formula,

$n=\dfrac{\lambda}{0.671\times\lambda}\\n=1.49$

Thus, the index of refraction of the material for which the wavelength of light is 0.671 times, the value of it in a vacuum is 1.49.

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