Question

Thirty-five (35.0) mL of ozone (O3) is stored at a temperature of 285 K and a pressure of 150.0 Pa. If the pressure is decreased to 125 Pa, what will be the new temperature?

Answer 1

Answer:

Temperature T2 = 237.5 K

Explanation:

Given:

Volume = 35 ml

T1 = 285 k

P1 = 150 pa

P2 = 125 pa

Find:

Temperature T2

Computation:

P1V/T1 = P2V/T2

150(35) / 285 = 125(35) / T2

Temperature T2 = 237.5 K