Given :
C) is a circle of center O and radius R=2 cm, and A is a point such that OA=3 cm.
There exist two circles of center A and tangent to (C).
To Find :
The radius of the new circles.
Solution :
Since, OA is 3 cm .
So, first circle with tangent to C if centre is at A is OA itself.
First radius, r = 3 cm.
And second circle is the on with radius , R = 3 + 2 = 5 cm.
Therefore, the radius of both the circles are 3 cm and 5 cm.
Hence, this is the required solution.