Question

Determine the margin of error, , for a 99% confidence interval when the sample size is =19 and the sample standard deviation is =10. Give your answer precise to three decimal places. =

Answer 1

Answer:

± 5.919

Step-by-step explanation:

Margin of Error formula = z × standard deviation/√n

Z score for 99% confidence interval = 2.58

n = 19

Standard deviation = 10

Margin of Error = 2.58 × 10/√19

= ± 5.9189259339

Approximately to 3 decimal place = ± 5.919