One light beam has wavelength, and frequency, fl. Another light beam has wavelength, in, and frequency, f2. Write a proportion that shows how the ratio of the wavelengths of these two light beams is related to the ratio Of their frequencies.

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One light beam has wavelength, [tex]\lambda_{1}[/tex], and frequency, f₁. Another light beam has wavelength, [tex]\lambda_{2}[/tex], and frequency, f₂. Write a proportion that shows how the ratio of the wavelengths of these two light beams is related to the ratio of the frequencies.

Answer: [tex]\frac{f_{1}}{f_{2}} =\frac{\lambda_{2}}{\lambda_{1}}[/tex]

Explanation: In vacuum, eletromagnetic waves travels at a constant speed called "speed of light", whose symbol is [c] and magnitude is 3x10⁸m/s.

Speed of light, frequency and wavelength are related by the formula:

[tex]c=\lambda.f[/tex]

So, if one light beam has wavelength and frequency, [tex]\lambda_{1}[/tex] and f₁, respectively, the second beam has wavelength [tex]\lambda_{2}[/tex] and frequency f₂ and both travel at speed of light:

[tex]\lambda_{1}f_{1}=\lambda_{2}f_{2}[/tex]

[tex]\frac{f_{1}}{f_{2}}=\frac{\lambda_{2}}{\lambda_{1}}[/tex]

Then, the ratio that shows the relation between frequencies and wavelengths of these light beams is [tex]\frac{f_{1}}{f_{2}}=\frac{\lambda_{2}}{\lambda_{1}}[/tex]

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