Answer:
The theorem requiring proof;
A transversal perpendicular to one of two parallel lines is also perpendicular to the other parallel line
The two column proof is as follows
Statement [tex]{}[/tex] Reason
RS ⊥ CD [tex]{}[/tex] Given
AB ║ CD [tex]{}[/tex] Given
The Slope of AB = The slope of CD [tex]{}[/tex] definition of parallel lines
The Slope of RS = -1/(The slope of CD) [tex]{}[/tex] definition of perpendicular lines
The Slope of RS = -1/(The slope of AB) [tex]{}[/tex] transitive property of equality
The Slope of RS = -1/(The slope of AB) [tex]{}[/tex] definition of perpendicular lines
RS ⊥ AB
Step-by-step explanation: