Answer:
Option B. 261 KPa.
Explanation:
From the question given above, the following data were obtained:
Initial volume (V1) = 200 mL
Initial pressure (P1) = 110 kPa
Initial temperature (T1) = 275 K.
Final volume (V2) = 95 mL
Final temperature (T2) = 310 K
Final pressure (P2) =?
The new pressure (P2) can be obtained by using the following formula as illustrated below:
P1V1 /T1 = P2V2 /T2
110 × 200/275 = P2 × 95/310
22000 / 275 = P2 × 95/310
80 = P2 × 95/310
Cross multiply
80 × 310 = P2 × 95
24800 = P2 × 95
Divide both side by 95
P2 = 24800/95
P2 = 261 KPa.
Thus, the new pressure of the gas is 261 KPa.
