Question

4/5 of Peter's money is twice as much as Weimin's money. What fraction of Peter's money is Weinim's money?

Answer 1

Answer:  $\dfrac25$

Step-by-step explanation:

As per given,

$\dfrac45\times(\text{Peter's money})=2 (\text{Weimin's money})$

Let x= Weimin's money

Then $\dfrac45\times(\text{Peter's money})=2x$

$\text{Peter's money}=2x\times\dfrac54\\\\\Rightarrow\ \text{Peter's money}=\dfrac52x$

The required fraction= $\dfrac{\text{Weinim's money}}{\text{Peter's money}}$

$=\dfrac{x}{\dfrac{5}{2}x}=\dfrac{1}{\dfrac52}\\\\\\=\dfrac25$

Hence, Required fraction = $\dfrac25$