Question

Find the 18th term of the arithmetic sequence whose common difference is d = 2 and whose first term is a, = 3.

Answer 1

Answer:

The 18th term of the arithmetic sequence will be:

$a_{18}=37$

Step-by-step explanation:

We know that the arithmetic sequence with a common difference 'd' and the first term 'a₁' is defined as

$a_n=a_1+\left(n-1\right)d$

Given the values

d = 2

a₁ = 3

As we have to determine the 18th term of the arithmetic sequence.

so putting n = 18 in the nth term to determine the 18th term.

$a_n=a_1+\left(n-1\right)d$

$a_{18}=3+\left(18-1\right)2$

     $=3+17\cdot \:2$

     $=3+34$

     $=37$

Therefore, the 18th term of the arithmetic sequence will be:

$a_{18}=37$