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Answer:
The equation in the standard form is
[tex]y+2x=5[/tex]
Step-by-step explanation:
Given the points
Finding the slope between (6, -7) and (4, -3)
[tex]\left(x_1,\:y_1\right)=\left(6,\:-7\right),\:\left(x_2,\:y_2\right)=\left(4,\:-3\right)[/tex]
[tex]\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m=\frac{-3-\left(-7\right)}{4-6}[/tex]
[tex]m=-2[/tex]
As the point-slope form is defined as
[tex]y-y_1=m\left(x-x_1\right)[/tex]
substituting the values m = -2 and the point (6, -7)
[tex]y-y_1=m\left(x-x_1\right)[/tex]
[tex]y-\left(-7\right)=-2\left(x-6\right)[/tex]
Writing the equation in the standard form form
As we know that the equation in the standard form is
[tex]Ax+By=C[/tex]
where x and y are variables and A, B and C are constants
converting the equation in standard form
[tex]y-\left(-7\right)=-2\left(x-6\right)[/tex]
[tex]y+7=-2\left(x-6\right)[/tex]
subtract 7 from both sides
[tex]y+7-7=-2\left(x-6\right)-7[/tex]
[tex]y=-2x+5[/tex]
[tex]y+2x=5[/tex]
Therefore, the equation in the standard form is
[tex]y+2x=5[/tex]