Question

1. A cyclist accelerates from 7 m/s to 11 m/s in two seconds. What is his acceleration?
m/s/s

Answer 1

Answer:

$\boxed {\boxed {\sf 2 \ m/s^2}}$

Explanation:

Acceleration can be found by dividing the change in velocity by the time.

$a=\frac{v_f-v_i}{t}$

The final velocity is 11 meters per second and the initial velocity is 7 meters per second. The time is 2 seconds.

$v_f=11 \ m/s\\v_i=7 \ m/s\\t= 2 \ s$

Substitute the values into the formula.

$a=\frac{11 \ m/s-7 \ m/s}{2 \ s}$

Solve the numerator.

• 11 m/s - 7 m/s = 4 m/s

$a=\frac{4 \ m/s}{2 \ s}$

Divide.

$a= 2 \ m/s/s$    or     $a= 2 \ m/s^2$

The acceleration of the cyclist is 2 meters per second squared.