Question

2.83 kJ are added to a sample of water at 100°C and it completely vaporizes. What is the
mass of the water?
general formula

Answer 1

Answer:

0.0013kg

Explanation:

Given parameters:

Quantity of heat  = 2.83kJ

Temperature  = 100°C

Unknown:

Mass of the water = ?

Solution:

The amount of heat needed to vaporize a substance is dependent on the mass of the substance and its latent heat of vaporization.

     H  = mL

H is the amount of heat

m is the mass

L is the latent heat of vaporization

  Latent heat of vaporization of water  =  2260 kJ/kg

Now insert the parameters and solve;

      2.83  = m x 2260

            m  = $\frac{2.83}{2260}$   = 0.0013kg