Question

1E. The number 2A5A0A2 is divisible by 99. What is the digit A?

Answer 1

We know, a number is divisible by 9 if the sum of digits is also divisible by 9.

Also, since A is an digit, so A is in between 0 to 9.

2+A+5+A+0+A+2  = 3A + 9

3A + 9 should be divisible by 9.

3A + 9 = 9n

A = (9n -9)/3

For n= 1 :

A = 0

For n=2 :

A = 3

For n= 3 :

A = 9

After this A > 9 which is not accepted.

Therefore, the digit A can be 0, 3 and 9 .

Hence, this is the required solution.

Answer 2

The digit A that makes 2A5A0A2 to be divisible by 99 is;

A = 3

• From study of divisibility of single digit numbers, it was discovered that a number can be divisible by 9 or a multiple of 9 provided the sum of digits is also divisible by 9.

• We are given the number 2A5A0A2

A is a single digit and as such will be between 0 and 9.

Thus, using the principle above;

2 + A + 5 + A + 0 + A + 2  = 3A + 9

• Applying the principle;

3A + 9 must be divisible by 9.

Thus;

3A + 9 = 9x

A = (9x - 9)/3

When x = 1;

A = 0

When x = 2;

A = 3

When x = 3;

A = 9

• Since A is a single digit, then it means that x cannot be more than 4 as any value of x more than 4 will yield a value of A that is not a single digit.

• Now, when we place either the value of 0, 3 or 9 for A into the given number, the only one that yields a number that is divisible by 99 is A = 3

Read more at; https://brainly.com/question/19299358