A 10,000-gallon swimming pool needs to be emptied. Exactly 2,000 gallons have already been pumped out of the pool and into the tanker. As the pump is pumping water, the amount of water in the pool decreases at a constant rate of 720 gallons per hour. What is the slope and what is the y-intercept

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Answer:

slope = -720

y-intercept: 8,000

Step-by-step explanation:

The slope in this case is a negative slope, since the word "decreased" is being used. The rate of 720 gallons per hour can be seen as -720 / 1, which gives you the -720 slope.

The y-intercept in an equation represents the initial value. Since 2,000 gallons has already been pumped out, the initial value is 8,000.

The constant rate at which the water decreases results in a straight line

function between the volume of water in the tank and time of pumping.

The slope is -720 (gal/hour)

The y-intercept is 8,000 (gallons)

Reasons:

The volume of the swimming pool = 10000 gallon

Volume of water already pumped out = 2,000 gallons

Rate at which the water is being pumped out = 720 gallons per hour

Required:

The slope and y-intercept of the function

Solution:

Volume of water in the tank = (10,000 - 20,000) gallons = 8,000 gallons

Volume of water decreasing from the tank after t hours = 720·t

Therefore;

Volume of water in the tank after t hours, is V(t) = 8000 - 720·t

Comparing the above function with the equation of a straight line, in slope

and intercept form, y = m·x + c, we have;

V(t) = -720·t + 8000

  • Slope, m = -720
  • y-intercept = 8000

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