Using the information given, it is found that:
a.
The standard error for the difference is of 0.0176.
The 95% confidence interval is 0.0151 to 0.0841.
b.
Since 0 is not part of the confidence interval, it is not plausible that there is no difference between males and females in the proportion who agree that each person has only one true love.
For males, we have that:
[tex]n = 1213, p_M = \frac{372}{1213} = 0.3067, s_M = \sqrt{\frac{0.3067(0.6933)}{1213}} = 0.01324[/tex]
For females, we have that:
[tex]n = 1412, p_F = \frac{363}{1412} = 0.2571, s_F = \sqrt{\frac{0.2571(0.7429)}{1412}} = 0.01163[/tex]
The distribution of differences has mean and standard error given by:
[tex]p = p_M - p_F = 0.3067 - 0.2571 = 0.0496[/tex]
[tex]s = \sqrt{s_M^2 + s_F^2} = \sqrt{0.01324^2 + 0.01163^2} = 0.0176[/tex]
It is given by:
[tex]p \pm zs[/tex]
z is the critical value, which considering that there is a 95% confidence level, it is of z = 1.96.
Then:
[tex]p - zs = 0.0496 - 1.96(0.0176) = 0.0151[/tex]
[tex]p + zs = 0.0496 + 1.96(0.0176) = 0.0841[/tex]
The 95% confidence interval is 0.0151 to 0.0841.
Item b:
Since 0 is not part of the confidence interval, it is not plausible that there is no difference between males and females in the proportion who agree that each person has only one true love.
More can be learned about confidence intervals at https://brainly.com/question/16162795