Answer:
5.3 mol CO₂
General Formulas and Concepts:
Chemistry - Stoichiometry
Explanation:
Step 1: Define
3.2 × 10²⁴ molecules CO₂
Step 2: Convert
[tex]3.2 \cdot 10^{24} \ mc \ CO_2(\frac{1 \ mol \ CO_2}{6.022 \cdot 10^{23} \ mc \ CO_2} )[/tex] = 5.31385 mol CO₂
Step 3: Check
We are given 2 sig figs. Follow sig fig rules.
5.31385 mol CO₂ ≈ 5.3 mol CO₂