Answer:
B. [tex]46.8\ \text{m}^3[/tex]
Step-by-step explanation:
a = Hexagonal edge length = 3 m
h = Height of pyramid = 6 m
Volume of right hexagonal pyramid is given by
[tex]V=\dfrac{\sqrt{3}}{2}a^2h[/tex]
[tex]\Rightarrow V=\dfrac{\sqrt{3}}{2}\times 3^2\times 6[/tex]
[tex]\Rightarrow V=46.76\approx 46.8\ \text{m}^3[/tex]
The volume of the pyramid is [tex]46.8\ \text{m}^3[/tex]