Question

As shown in the diagram below, a rope attached to a 500.-kilogram crate is used to exert a force of 45 newtons at an angle of 65 degrees above the horizontal. The horizontal component of the force acting on the crate is:

1) 19N
2) 41N
3) 210N
4) 450N

Answer 1

Answer:

19N

Explanation:

Sorry i don’t really know why that’s the answer just that i know thats correct. so what the thing i looked up said

45N(cosine65)= horizontal component

45N(0.423)=19N and that’s the answer

i don’t know where the .423 came from but i hoped i helped :)

Answer 2

Answer: 1

Explanation:

Given

Mass of Crate $m=500\ kg$

Applied force $F=45\ N$ at an angle of $\theta=65^{\circ}$

The applied force can be resolved in to two direction i.e. vertical and horizontal direction.

From the figure, horizontal component of the force is $F\cos 65^{\circ}$

$\Rightarrow F\cos65^{\circ}=45\cos 65^{\circ}\\\\\Rightarrow 19.017\approx 19\ N$

Thus, the horizontal component of force is $\mathbf{19\ N}$

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